Comments

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  1

  

  TICHPX  commented on Oct. 14, 2021, 4:06 a.m. ← edited →

  code tham khảo

  #include<bits/stdc++.h>
  using namespace std;
  int main()
  {
      int x1,x2,x3,y1,y2,y3;
      cin>>x1>>y1>>x2>>y2>>x3>>y3;
      cout<<(x1^x2^x3)<<" "<<(y1^y2^y3);
  }

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  2

  

  ga123  commented on Oct. 14, 2021, 5:24 a.m.

  chỗ Y3 hình như là y thường , chỗ dòng cin ạ

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  1

  

  LãoTam  commented on Sept. 6, 2021, 2:10 p.m. ← edited →

  //#include<conio.h>
  #include<stdio.h>
  #include<iostream>
  
  using namespace std;
  int main()
  {
      long long a,b,c,d,e,f;
      cin>>a>>b>>c>>d>>e>>f;
      if(a==c) cout<<e;
      else if(a==e) cout<<c;
      else cout<<a;
      cout<<" ";
      if(b==d) cout<<f;
      else if(d==f) cout<<b;
      else cout<<d;
     // getch();
  }

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  1

  

  Namguitar  commented on Oct. 24, 2020, 1:38 a.m. ← edited →

  #include <stdio.h>
  #include <math.h>
  int main ()
  {
      int i;
  float x[3],y[3];
  for(i=1;i<=3;i++)
  {
      scanf("%f",&x[i]);
      scanf ("%f", &y[i]);
  }
  x[3]= x[2]-x[1]+x[0]; 
  y[3]= y[2]-y[1]+y[1];
  printf ("%f%f", x[3],y[3]);
  }

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  1

  

  TICHPX  commented on Oct. 24, 2020, 5:13 a.m.

  Up code nhớ đưa vào trong

  code

  nhé