0.SF. The Hamming Distance


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Points: 3 (partial)
Time limit: 1.0s
Memory limit: 98M

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Problem type

The Hamming distance between two strings of bits (binary integers) is the number of corresponding bit positions that di?er. This can be found by using XOR on corresponding bits or equivalently, by adding corresponding bits (base 2) without a carry. For example, in the two bit strings that follow:

A 0 1 0 0 1 0 1 0 0 0

B 1 1 0 1 0 1 0 1 0 0

A XOR B = 1 0 0 1 1 1 1 1 0 0

The Hamming distance (H) between these 10-bit strings is 6, the number of 1s in the XOR string.

Input

Input consists of several datasets. The ?rst line of the input contains the number of datasets, and its followed by a blank line. Each dataset contains N, the length of the bit strings and H, the Hamming distance, on the same line. There is a blank line between test cases.

Output

For each dataset print a list of all possible bit strings of length N that are Hamming distance H from the bit string containing all 0s (origin). That is, all bit strings of length N with exactly H 1s printed in ascending lexicographical order.

The number of such bit strings is equal to the combinatorial symbol C(N;H). This is the number of possible combinations of NH zeros and H ones. It is equal to

                    N!
                  (NH)!H!

This number can be very large. The program should work for 1 = < H = < N = < 16. Print a blank line between datasets.

Examples

Input 2

4 2

1 0

Output

0011

0101

0110

1001

1010

1100

0


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